Which statement correctly demonstrates throwing a new exception in Java?

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Multiple Choice

Which statement correctly demonstrates throwing a new exception in Java?

Explanation:
Throwing a new exception in Java is done with the throw keyword, which passes control to the runtime to locate a matching catch block or to propagate up the call stack. You must first create the exception object and then throw it: throw new SomeException(...); Merely constructing the exception doesn't affect program flow until you use throw. The other constructs don't throw; catch is for handling exceptions that have already been thrown, not for initiating them; try is for grouping code that may throw and is followed by catch blocks, not for creating an exception; and there is no invoke keyword for this operation. If the exception is checked, the method must declare it with throws or handle it.

Throwing a new exception in Java is done with the throw keyword, which passes control to the runtime to locate a matching catch block or to propagate up the call stack. You must first create the exception object and then throw it: throw new SomeException(...); Merely constructing the exception doesn't affect program flow until you use throw. The other constructs don't throw; catch is for handling exceptions that have already been thrown, not for initiating them; try is for grouping code that may throw and is followed by catch blocks, not for creating an exception; and there is no invoke keyword for this operation. If the exception is checked, the method must declare it with throws or handle it.

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